Q.1 Find the S.P ,when

(a) C.P=200 Rs and Gain =2\frac{1}{2}%

(b) C.P=1000 Rs and loss =5\frac{1}{4}%

Q.2 An article was bought for 80Rs and sold for 96Rs. The gain percent is

Q.3 A shopkeeper sold an article for 720Rs at a loss of 10 %. At what price should he sell it so as to gain 5 %?

Q.4 Raju sold two fans for 990Rs each. On selling one fan, he had a gain of 10 % and on selling another fan, he had a loss of 10 %. Find his gain or loss percent in the whole transaction

Solution:

Q.1

Find the S.P,when

(a) C.P=200 Rs and Gain =2\frac{1}{2}%

(b) C.P=1000 Rs and loss =5\frac{1}{4}%

Solution:(a)

Cost Price =200 Rs

Gain Percentage=2\frac{1}{2}%

We Know ,

S.P=\frac{100+gain\ \%\ }{100} \times \ C.P

S.P=\frac{100+2\frac{1}{2} \%\ }{100} \times \ 200

S.P=\frac{100+\frac{5}{2} \%\ }{100} \times \ 200

S.P=\frac{205}{200} \times 200

S.P= 205 Rs

Solution :(b)

Cost Price = 1000 Rs

Loss Percentage= 5\frac{1}{4}%

We Know ,

S.P=\frac{100-loss\ \%\ }{100} \times \ C.P

S.P=\frac{100-5\frac{1}{4} \%\ }{100} \times \ 1000

S.P=947.57Rs

**Problem: 2**

An article was bought for 80Rs and sold for 96Rs. The gain percent is

Solution:

Cost Price (C.P)= 80 Rs

Selling Price (S.P)= 96 Rs

We Know ,

Profit = S.P-C.P

Profit=96-80=16

Profit% =\frac{profit}{C.P}×100

Profit % =\frac{16}{80}×100

Profit%=20 %

**Problem: 03 **

A shopkeeper sold an article for 720Rs at a loss of 10 %. At what price should he sell it so as to gain 5 %?

Solution:

It is given that ,

Selling Price of article(S.P) = 720 Rs

Loss percentage=10 %

So, Cost Price of article (C.P) =\frac{S.P\times 100}{100-loss\ \%}

C.P=\frac{720Rs×100}{100-10}

C.P= \frac{7200}{9}

C.P= 800 Rs

Now Required gain percentage = 5%

Selling price of article (S.P) =\frac{100+gain\%}{100} \times C.P

S.P= \frac{(100+5) (800) }{100}

S.P= 840Rs

Problem : 04

Raju sold two fans for 990Rs each. On selling one fan, he had a gain of 10 % and on selling another fan, he had a loss of 10 %. Find his gain or loss percent in the whole transaction

Solution:

It is given that,

The selling Price (S.P) of each fan is 990 Rs

Let two fans are f1 and f2

So,by selling each fan he got a gain of 10 % on f1 and a loss of 10 % of f2

C.P of f1 =\frac{S.P\times 100}{100+gain\%}

C.P=\frac{990×100}{100+10}

C.P= 900 Rs

Whereas on f2

C.P =\frac{S.P\times 100}{100-loss\%}

C.P= \frac{990×110}{100-10}

C.P=1100 Rs

Total Cost price (C.P) of both fans =900Rs +1100Rs =2000Rs

Total Selling price (S.P) of both fans= 990Rs ×2=1980Rs

Loss = Total C.P-Total S.P

Loss= 2000Rs-1980Rs

Loss= 20 Rs

We Know,

Loss % =\frac{Loss}{Total C.P}×100 %

Loss % = \frac{20}{2000}×100

Loss % = 1 %