Q.1 The product of two numbers is 21\frac{3}{4}.If one of the number is \frac{15}{32},find the other

Solution:

Let the other number be x

If the product of two numbers is 21\frac{3}{4} , then

\frac{15}{32} × x= 21\frac{3}{4}

\frac{15x}{32} = \frac{87}{4}

Multiplying both side by \frac{32}{15} ,we get

\frac{15}{32} × \frac{32}{15} × x = \frac{87}{4}

⇒ x =\frac{232}{5} or 46\frac{2}{5}

Hence , required number is 46\frac{2}{5}

Q.2 By what number should 1\frac{3}{4} be divided to get 1\frac{5}{16}?

Solution:

Let the required number be x

∴ 1\frac{3}{4} ÷ x = 1\frac{5}{16}

⇒ \frac{7}{4} × \frac{1}{x} = \frac{21}{16}

⇒ \frac{7}{4x} = \frac{21}{16}

⇒ 7 × 16 = 21 × 4x

⇒ 112 = 84 x

∴ x=\frac{112}{84}=\frac{4}{3}

Hence , required number is \frac{4}{3}

[Best sample paper for class 7 ]

Q.3 If the cost of 7\frac{1}{2} kg apples is 600 Rs, find the cost of 1 kg apples

Solution:

Cost of 7\frac{1}{2} kg apples = 600 Rs

or

Cost of \frac{15}{2} kg apples = 600 Rs

∴ Cost of 1 kg apple = 600 ÷ \frac{15}{2}

⇒ Cost of 1 kg apple = 600 × \frac{2}{15}

⇒ Cost of 1 kg apple = 40×2=80 Rs

Q.4 A rope of the length 8\frac{1}{3} m is cut into 5 pieces of equal length. Find the length of each piece.

Solution:

Length of the rope = 8\frac{1}{3} m or \frac{25}{3}

If rope cut into 5 equal pieces, then

Length of each piece is given by = \frac{25}{3} ÷ 8

⇒ Length of each piece = \frac{25}{3} × \frac{1}{8}

⇒ Length of each piece = \frac{25}{24} m

Q.5 The quotient of two numbers is 2 . If the denominator is 7\frac{2}{5}, find the numerator.

Solution:

Quotient of two numbers =2

If the denominator of the fraction = 7\frac{2}{5} or \frac{37}{5}.

We know , \frac{Numerator}{Denominator}= Quotient

⇒ \frac{numerator}{\frac{37}{5}}= 2

⇒ Numerator × \frac{5}{37} = 2

⇒ 5 Numerator = 74

Hence , Numerator = \frac{74}{5}.

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